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    <title>Approximation on Understanding the Riemann Hypothesis</title>
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    <managingEditor>markus@recommend.games (Markus Shepherd)</managingEditor>
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    <lastBuildDate>Sun, 23 Nov 2014 10:47:17 +0000</lastBuildDate>
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      <title>Applying the Explicit Formula</title>
      <link>https://riemannhypothesis.blog/2014/11/applying-the-explicit-formula/</link>
      <pubDate>Sun, 23 Nov 2014 10:47:17 +0000</pubDate><author>markus@recommend.games (Markus Shepherd)</author>
      <guid>https://riemannhypothesis.blog/2014/11/applying-the-explicit-formula/</guid>
      <description>It&amp;rsquo;s quite some time since we arrived at Riemann&amp;rsquo;s main result, the explicit formula&#xA;\[ J(x)=\mathrm{Li}(x)-\sum_{\Im\varrho&amp;gt;0}\left(\mathrm{Li}(x^\varrho)+\mathrm{Li}(x^{1-\varrho})\right)+\int_x^\infty\frac{\mathrm{d}t}{t(t^2-1)\log t}-\log2, \]&#xA;where \(J(x)\) is the prime power counting function introduced even earlier. It&amp;rsquo;s high time we applied this!&#xA;First, let&amp;rsquo;s take a look at \(J(x)\) when calculating it exactly:&#xA;You see how this jumps by one unit at prime values (\(2\), \(3\), \(5\), \(7\), \(11\), \(13\), \(17\), \(19\)), by half a unit at squares of primes (\(4\), \(9\)), by a third at cubes (\(8\)), and by a quarter at fourth powers (\(16\)), but is constant otherwise.</description>
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