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    <title>Zeta function on Understanding the Riemann Hypothesis</title>
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    <description>Recent content in Zeta function on Understanding the Riemann Hypothesis</description>
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    <managingEditor>markus@recommend.games (Markus Shepherd)</managingEditor>
    <webMaster>markus@recommend.games (Markus Shepherd)</webMaster>
    <lastBuildDate>Wed, 31 May 2017 05:41:25 +0000</lastBuildDate>
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      <title>The Prime Bet</title>
      <link>https://riemannhypothesis.blog/2017/05/the-prime-bet/</link>
      <pubDate>Wed, 31 May 2017 05:41:25 +0000</pubDate><author>markus@recommend.games (Markus Shepherd)</author>
      <guid>https://riemannhypothesis.blog/2017/05/the-prime-bet/</guid>
      <description>Let&amp;rsquo;s say you sit in a pub, minding your own business, when all of a sudden a stranger walks up to you and offers you a bet:&#xA;We&amp;rsquo;ll choose two positive integers at random. If they have any divisor in common (other than \(1\)) I&amp;rsquo;ll pay you a dollar, else you&amp;rsquo;ll pay me a dollar. Are you in?&#xA;Apart from the question what kind of establishments you frequent, you should be wondering: is this a good bet for you?</description>
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      <title>Visualising the Riemann Hypothesis</title>
      <link>https://riemannhypothesis.blog/2016/04/visualising-the-riemann-hypothesis/</link>
      <pubDate>Sun, 10 Apr 2016 18:59:25 +0000</pubDate><author>markus@recommend.games (Markus Shepherd)</author>
      <guid>https://riemannhypothesis.blog/2016/04/visualising-the-riemann-hypothesis/</guid>
      <description>Update 2024-10-20: Watch the video now in 4K!&#xA;One stubborn source of frustration when working with complex numbers is the fact that visualisation becomes tedious, if not impossible. Complex numbers have 2 &amp;ldquo;real&amp;rdquo; dimensions in themselves, which give rise to the complex plane. That&amp;rsquo;s all good and fair. But if you talk about a function with complex domain and codomain, you already deal with a 4-dimensional graph. Unfortunately, my mind can only handle 3 dimensions (on a good day).</description>
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      <title>Applying the Explicit Formula</title>
      <link>https://riemannhypothesis.blog/2014/11/applying-the-explicit-formula/</link>
      <pubDate>Sun, 23 Nov 2014 10:47:17 +0000</pubDate><author>markus@recommend.games (Markus Shepherd)</author>
      <guid>https://riemannhypothesis.blog/2014/11/applying-the-explicit-formula/</guid>
      <description>It&amp;rsquo;s quite some time since we arrived at Riemann&amp;rsquo;s main result, the explicit formula&#xA;\[ J(x)=\mathrm{Li}(x)-\sum_{\Im\varrho&amp;gt;0}\left(\mathrm{Li}(x^\varrho)+\mathrm{Li}(x^{1-\varrho})\right)+\int_x^\infty\frac{\mathrm{d}t}{t(t^2-1)\log t}-\log2, \]&#xA;where \(J(x)\) is the prime power counting function introduced even earlier. It&amp;rsquo;s high time we applied this!&#xA;First, let&amp;rsquo;s take a look at \(J(x)\) when calculating it exactly:&#xA;You see how this jumps by one unit at prime values (\(2\), \(3\), \(5\), \(7\), \(11\), \(13\), \(17\), \(19\)), by half a unit at squares of primes (\(4\), \(9\)), by a third at cubes (\(8\)), and by a quarter at fourth powers (\(16\)), but is constant otherwise.</description>
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